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(x-7)(2x+5)-(x-4)^2=9x-27
We move all terms to the left:
(x-7)(2x+5)-(x-4)^2-(9x-27)=0
We get rid of parentheses
(x-7)(2x+5)-(x-4)^2-9x+27=0
We multiply parentheses ..
(+2x^2+5x-14x-35)-(x-4)^2-9x+27=0
We add all the numbers together, and all the variables
(+2x^2+5x-14x-35)-9x-(x-4)^2+27=0
We get rid of parentheses
2x^2+5x-14x-9x-(x-4)^2-35+27=0
We add all the numbers together, and all the variables
2x^2-18x-(x-4)^2-8=0
We move all terms containing x to the left, all other terms to the right
2x^2-18x-(x-4)^2=8
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